Question

The smallest number which contains $7936$ as a factor and is a perfect square is:

• A. $12008$
• B. $246016$
• C. $61504$
• D. $240616$

Answer 1

The correct option is B $246016$

Let us first find the prime factors of $7936$ as follows:

$7936=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 31=2^2\times 2^2\times 2^2\times 31$

Now, to make $7936$ as a perfect square, we have to multiply $7936$ with $31$ that is:

$7936\times 31=246016$

Hence, the smallest number which contains $7936$ as a factor and is a perfect square is $246016$.