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Question

The smallest number which when diminished by 3 is divisible by 14, 28, 36 and 45, is
(a) 1257
(b) 1260
(c) 1263
(d) none of these

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Solution

(c) 1263

The smallest number that is exactly divisible by 14, 28, 36 and 45 will be their L.C.M.
So, the required number will be the L.C.M. plus 3.



L.C.M. of the three numbers = 22 × 32 × 5 × 7
= 1260
∴ Required number = 1260 + 3 = 1263

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