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Question

The smallest number which when divided by 20, 25, 35 and 40 and leaves a remainder of 14, 19, 29 and 34 respectively is

A
1394
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B
1404
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C
1664
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D
1406
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Solution

The correct option is A 1394
L.C.M. = 5×2×2×5×7×2=1400
20 - 14 = 25 - 19 = 35 - 29
= 40 - 34 = 6
required number
= LCM - 6
= 1400 - 6
= 1394
1068666_415711_ans_3fb1740f434d475db1be0b80f99ebc32.bmp

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