Question

The smallest number which when divided by 20, 25, 35 and 40 and leaves a remainder of 14, 19, 29 and 34 respectively is

• A. $1394$
• B. $1404$
• C. $1664$
• D. $1406$

Answer 1

The correct option is A $1394$

$\therefore$ L.C.M. = $5\times 2\times 2\times 5\times 7\times 2=1400$

20 - 14 = 25 - 19 = 35 - 29
= 40 - 34 = 6
$\therefore$ required number
= LCM - 6
= 1400 - 6
= 1394