Question

The smallest number which when divided by $20,25,35$ and $40$ and leaves a remainder of $14,19,29$ and $34$, respectively is

• A. $1394$
• B. $1404$
• C. $1664$
• D. $1406$

Answer 1

The correct option is A $1394$

$\therefore$ LCM =$5\times 2\times 2\times 5\times 7\times 2=1400$
$20-14=25-19=35-29=40-34=6$
$\therefore$ Required number$=LCM-6=1400-6=1394.$