The smallest number which when divided by $4, 6, 10, 15$ gives the same remainder $3$ is

75

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123

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63

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39

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Solution

The correct option is C $63$
L.C.M of $4, 6, 10 a n d 15$
$4 = 2 \times 2$
$6 = 2 \times 3$
$10 = 2 \times 5$
$15 = 3 \times 5$
L.C.M of $4, 6, 10 a n d 15 = 2 \times 2 \times 3 \times 5 = 60$
$∴ t h e r e q u i r e d n u m b e r = 60 + 3 = 63$

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