The smallest number which when reduced by 7 is divisible by 12, 16 & 18 :

199

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223

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295

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287

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Solution

The correct option is C 295
$295 - 7 = 288$
When divided by 12 we get = $\frac{288}{12} = 24$

When divided by 16 we get = $\frac{288}{16} = 18$
When divided by 18 we get = $\frac{288}{18} = 16$

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Similar questions

Find the smallest number which when reduced by 2 is divisible by 5 and 7

7

12

16

18

21

28

2

12, 16, 18, 21

28

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