The smallest number which when reduced by 7 is divisible by 12,16 and 18:
A
199
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B
223
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C
151
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D
287
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Solution
The correct option is B151 Taking LCM of 12,16 & 18 will give the smallest number divisible by 12,16 & 18. The LCM =144 So the smallest number =144+7=151 Hence, option C is the correct answer.