Question

The smallest possible integer that leaves remainders 2, 3, and 4 when divided by 3, 4, and 5, respectively, is

• A. 40
• B. 47
• C. 59
• D. 77

Answer 1

Answer: (C)

59

Let the number is N which when divide by 3,4 , 5 leaves reminder It means N+1 should divide by 3, 4 and 5
If the number is completely divide means it should be multiple of 3,4, and 5
$\therefore N+1=3\times 4\times 5=60$
$N+1=60$
$N=60-1=59$
Hence lowest number would be $59$