Question

The smallest surface area of a cuboid made up of $12.1c{m}^3$ will be?

Answer 1

Given: Volume of cuboid $=12.1c{m}^3$

$\Rightarrow l\times b\times h=12.1$

Smallest surface area of a cuboid is only possible when all its dimensions are equal.

Therefore, $l=b=h=12.1$

$\Rightarrow l^3=12.1$

$\therefore l\sim 2.3cm$

Hence, total surface area of cuboid $2(lb+bh+lh)$

$=2\times ({2.3}^2+{2.3}^2+{2.3}^2)$

$=31.74c{m}^2$