The smallest three digit number when divided by 12, 16 and 18 leaves in each case a remainder 5, is

149

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293

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337

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481

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Solution

The correct option is A 149
The required number is 5 added to the l.c.m. of 12, 16 and 18.
l.c.m. of 12, 16 and 18 is 144.
So, the required number is $144 + 5 = 149$

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