The smallest value of k, for which both the roots of the equation x2−8kx+16(k2−k+1) = 0 are real, distinct and have values at least 4,is
2
α and β ≥4
x2−8kx+16(k2−k+1)=0
(i) D > 0
64 k2−64(k2−k+1) > 0
k - 1 > 0 ⇒ k > 1
(ii) 8k2 > 4 ⇒ k > 1
(iii) f(4) ≥ 0
16 - 32k + 16 (k2−k+1)≥0
k2−3k+2≥0⇒k≤1 or k ≥ 2
∴ k ∈ [2,∞)
∴ least value of k = 2