The sodium salt of a certain weak monobasic organic acid is hydrolysed to an extent of 3% in its 0.1M solution at 25∘C. Given that the ionic product of water is 10−14 at this temperature, what is the dissociation constant of the acid ?
A
1×10−10
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B
1×10−9
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C
3.33×10−9
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D
3.33×10−10
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Solution
The correct option is A1×10−10 NaX+H2O⇌XH+NaOHBefore hydrolysis100After hydrolysisC(1−h)ChCh h=0.03 From salt hydrolysis, we know, Kh=Ch2=9×10−5 Kh=KwKa=9×10−5 ⇒Ka=10−149×10−5=1.11×10−10=1×10−10