Question

The sol given below with negatively charged colloidal particles is :

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Answer 1

When $AgN{O}_3$ solution is added to $KI$ solution
$AgN{O}_3\left(aq\right)+KI\left(aq\right)\to AgI\left(s\right)\downarrow +AgN{O}_3\left(aq\right)$
$AgI$ gets precipitated.
The precipitated silver iodide adsorbs iodide ions $\left(I^{-}\right)$ from the dispersion medium and negatively charged colloidal sol is formed $AgI/I^{-}$

When $KI$ solution is added to $AgN{O}_3$ solution
$AgN{O}_3\left(aq\right)+KI\left(aq\right)\to AgI\left(s\right)\downarrow +AgN{O}_3\left(aq\right)$
$AgI$ gets precipitated.

The precipitated silver iodide adsorbs $A{g}^{+}$ions from the dispersion medium and positively charged colloidal sol is formed $AgI/A{g}^{+}$
Option (b) is correct