Question

The solar energy incident on the roof in 1 hour of dimension $8m\times 20m$ will be

• A. $5.76\times {10}^{8}J$
• B. $5.76\times {10}^{7}J$
• C. $5.76\times {10}^{6}J$
• D. $5.76\times {10}^{5}J$

Answer 1

Answer: (A)

$5.76\times {10}^{8}J$

Here the power per unit area is given, $I={10}^{3}W/m^2$

So, the total power $=I\times$ area of roof $={10}^3\times (8\times 20)=1.6\times {10}^{5}W$

Since power is the energy divided by time so, energy, $E=Pt=1.6\times {10}^5\times \left(3600\right)=5.76\times {10}^{8}J$