The solid residue $(B)$ is:

C a O

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P b O

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Z n O

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B a O

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Solution

The correct option is D $B a O$
The sequence of reactions is given below.
$B a (N O_{3})_{2} h e a t - - \to B a O d i l H C l - ----- \to B a C l_{2} A B B a O A m m o n i u m c a r b o n a t e - ------------ \to B a C O_{3} d i l H C l - --- \to B a C l_{2} P o t a s s i u m c h r o m a t e - ----------- \to B a C r O_{4} d i l H_{2} S O_{4} - ------- \to B a S O_{4} C D E$
The white precipitate is of barium carbonate. The yellow precipitate (D) is of barium chromate. Barium sulfate precipitate is also white in color. The solid residue (B) is barium oxide.

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