Question

The solids are similar. Find the surface area of the red solid.Round your answer to the nearest tenth .

Answer 1

When two solids are similar the value of the ratio of their surface area is equal to the square of the value of the ratio of their corresponding linear measures.

$\frac{Surfaceareaofsolid1}{SurfaceAreaofsolid2}={\left(\frac{Widthofsolid1}{Widthofsolid2}\right)}^2$

$$\begin{gathered} \frac{608}{s}={\left(\frac{8}{5}\right)}^2 \\ \frac{608}{s}=\frac{64}{25} \\ S\times 64=608\times 25 \\ S=\frac{608\times 25}{64} \\ S=237.5 \end{gathered}$$

Final Answer: Surface area of red solid is $237.5m^2$