The solubility in water of a sparingly soluble salt AB2 is 1.0 × 10−5 mol l−1. Its
solubility product number will be
4 × 10−15
4 × 10−10
1 × 10−15
1 × 10−10
AB2 ⇋ A+ + 2B− At equilibrium, [A+] = 1 × 10−5,[B−] = 2 × 10−5
Ksp = [1 × 10−5][2 × 10−5]2 = 4 × 10−15
The solubility product of a sparingly soluble salt A2B is 3.2×10−11. Its solubility in molL−1 is:
If the solubility product Ksp of a sparingly soluble salt MX2 at 25∘C is
1.0 × 10−11, the solubility of the salt in mole/litre at this temperature will
be