Question

The solubility of a saturated solution of calcium fluoride is $2\times {10}^{-4}$ mole per litre. Its solubility product is:

• A. $32\times {10}^{-10}$
• B. $32\times {10}^{-8}$
• C. $32\times {10}^{-14}$
• D. $32\times {10}^{-12}$

Answer 1

The correct option is D $32\times {10}^{-12}$

The relationship between the solubility s and the solubility product $K_{sp}$ of calcium fluoride is as given below.
$K_{sp}ofCa{F}_2=4s^3$
Substitue values in the above expression.
$K_{sp}ofCa{F}_2=4s^3=4\times (2\times {10}^{-4}{)}^3=32\times {10}^{-12}$