The solubility of AgBr in the presence of AgSCN in water is x - 10-7 mol L -1- The -x- is - K sp AgSCN -0-96 - 10-12 mol 2 L -2- K sp AgBr -4-8 - 10-13 mol 2 L -2-

Let 'x' be the solubility of AgBr and y be the solubility of AgSCN. AgBr ⇌(x+y) xAg^+ + Br^ K_sp = 4.8 × 10^ 13 AgSCN ⇌(x+y) yAg^+ + SCN^ K_Sp = 0.96 × 10^ 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Solubility

The solubilit...

Question

The solubility of AgBr in the presence of AgSCN in water is $x \times 10^{- 7} m o l L^{- 1}$ . The 'x' is___
$[K_{s p} A g S C N = 0.96 \times 10^{- 12} m o l^{2} L^{- 2}, K_{s p} A g B r = 4.8 \times 10^{- 13} m o l^{2} L^{- 2}]$

Open in App

Solution

Let 'x' be the solubility of AgBr and y be the solubility of AgSCN.
$A g B r ⇌ A g^{+} + B r^{-} (x + y) x K_{s p} = 4.8 \times 10^{- 13} A g S C N ⇌ A g^{+} + S C N^{-} (x + y) y K_{S p} = 0.96 \times 10^{- 12} \frac{4.8 \times 10^{- 13}}{0.96 \times 10^{- 12}} = \frac{x}{y} = \frac{1}{2} K_{s p} A g B r = (x + y) x = 4.8 \times 10^{- 13} (x + 2 x) x = 4.8 \times 10^{- 13} x = 4 \times 10^{- 7} m o l / L$

Suggest Corrections

Similar questions

Q. The solubility of

A g B r

in the presence of

A g S C N

in water is

x \times 10^{- 7} m o l

L^{- 1}

. The

x

is ______
(

K_{s p} A g S C N = 0.96 \times 10^{- 12} M^{2}, K_{s p} A g B r = 4.8 \times 10^{- 13} M^{2}

)

Q. Calculate the simultaneous solubility of

A g S C N

and

A g B r

(K_{s p} (A g S C N) = 1.1 \times 10^{- 12}

K_{s p} (A g B r) = 5 \times 10^{- 13})

Q. The solubility of sparingly soluble salt

C d C O_{3}

2 \times 10^{- 6}

m o l L^{- 1}

25^{o} C

. The

K_{s p}

value for

C d C O_{3}

is:

Q. Calculate solubility of

A g C l

0.1 M N a C l

25^{o} C

if its solubility product at same temperature is

2.0 \times 10^{- 10} m o l^{2} L^{- 2}

If K_{s p} (A g C N S) = 1 \times 10^{- 12} and K_{s p} (A g B r) = 5 \times 10^{- 13}

then the values of simultaneous solubility of

A g C N S

and

A g B r

in a solution of water will be:

Join BYJU'S Learning Program

The solubility of AgBr in the presence of AgSCN in water is x×10−7mol L−1. The 'x' is___ [KspAgSCN=0.96×10−12mol2L−2,KspAgBr=4.8×10−13mol2L−2]

Let 'x' be the solubility of AgBr and y be the solubility of AgSCN. AgBr⇌Ag++Br−(x+y)xKsp=4.8×10−13AgSCN⇌Ag++SCN−(x+y)yKSp=0.96×10−124.8×10−130.96×10−12=xy=12KspAgBr=(x+y)x=4.8×10−13(x+2x)x=4.8×10−13x=4×10−7mol/L

The solubility of AgBr in the presence of AgSCN in water is $x \times 10^{- 7} m o l L^{- 1}$ . The 'x' is___
$[K_{s p} A g S C N = 0.96 \times 10^{- 12} m o l^{2} L^{- 2}, K_{s p} A g B r = 4.8 \times 10^{- 13} m o l^{2} L^{- 2}]$