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Common Ion Effect

The solubilit...

Question

The solubility of $A g I$ in $N a I$ solution is less than that in pure water because

A g I

forms complex with

N a I

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Of common ion effect

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Solubility product of

A g I

is less than that of

N a I

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The temperature of the solution decreases

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Solution

The correct option is A Of common ion effect
The common ion presence in the solution decrease the solubility of a given sparingly soluble compound. So, solubility of AgI in NaI solution is less.

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Similar questions

Q. The solubility product of

A g I

25^{0} C

1.0 \times 10^{- 16} M^{2}

. The solubility of

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K I

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is approximately: (in

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In order to determine solubility of sodium iodide (NaI), 150g of saturated solution of sodium iodide(NaI) is evaporated to dryness at $25^{0}$ C. At this stage 90 g of NaI is obtained. Find the solubility of NaI in water at $25^{\circ}$ C.

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K_{s p} (A g I) = 8.5 \times 10^{- 17}

. The solubility of

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^{o}

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1.0 \times 10^{- 16} m o l^{2} L^{- 2}

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is approximately (in mol L

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The solubility of AgI in NaI solution is less than that in pure water because

The correct option is A Of common ion effectThe common ion presence in the solution decrease the solubility of a given sparingly soluble compound. So, solubility of AgI in NaI solution is less.

The solubility of $A g I$ in $N a I$ solution is less than that in pure water because

The correct option is A Of common ion effect
The common ion presence in the solution decrease the solubility of a given sparingly soluble compound. So, solubility of AgI in NaI solution is less.