Question

The solubility of $Ba{F}_2$ in a solution of $Ba(N{O}_3{)}_2$ will be represented by the concentration term:-

• A. $\left[B{a}^{2+}\right]$
• B. $\left[F^{-}\right]$
• C. $\frac{1}{2}\left[F^{-}\right]$
• D. $2\left[N{O}_3^{-}\right]$

Answer 1

The correct option is C $\frac{1}{2}\left[F^{-}\right]$

Let $s$ be the solubility of $Ba{F}_2$ in $BaN{O}_3$ solution.
The expression for the solubility product is given by,
$K_{sp}=\left[B{a}^{2+}\right][F^{-}{]}^2$
The concentration of fluoride ions in the solution is as follows:
$\left[F^{-}\right]=2s$
Thus, $s=\frac{1}{2}\left[F^{-}\right]$.