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Question
The solubility of BaSO4 in water is 2.33×10−3gL−1. Its solubility product will be: (molecular weight of BaSO4=233)
(molecular weight of BaSO4=233)
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Solution
S=2.33×10−3233=10−5mol/LKSP of BaSO4=S2=10−5×10−5=10−10
S=2.33×10−3233=10−5mol/L
KSP of BaSO4=S2=10−5×10−5=10−10
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