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Question

The solubility of BaSO4 in water is 2.42 × 103 gL1 at 298 K. The value of its solubility product (Ksp) will be
(Given molar mass ofBaSO4 = 233 g mol–1)

A
1.08 × 1014 mol2L2
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B
1.08 × 1012 mol2L2
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C
1.08 × 1010 mol2L2
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D
1.08 × 108 mol2L2
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Solution

The correct option is C 1.08 × 1010 mol2L2
Solubility of BaSO4,s=2.42×103233(molL1)
=1.04×105(molL1)
BaSO4(s)Ba2+s(aq)+SO2+4s(aq)
KSP=[Ba2+][SO24]=s2
=(1.04×105)2
=1.08×1010mol2L2

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