The solubility of ${C a}_{3} {({P O}_{4})}_{2}$ in water is $y$ mol/L. Its solubility product is:

6 y^{4}

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36 y^{4}

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64 y^{5}

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108 y^{5}

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Solution

The correct option is D $108 y^{5}$
${C a}_{3} {({P O}_{4})}_{2} (s) ⇌ 3 {C a}^{2 +} 3 y (q) + 2 {P O}_{4}^{3 -} 2 y (a q)$

$∴ K_{s p} = {[{C a}^{2 +}]}^{3} \times {[{P O}_{4}^{3 -}]}^{2}$

$= {(3 y)}^{3} \cdot {(2 y)}^{2} = 27 y^{3} \times {4 y}^{2} = 108 y^{5}$

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