Question

The solubility of calomel in water at ${25}^{\circ }C$ is $x$ moles/lit. Its solubility product is:

• A. $4x^3$
• B. $12x^3$
• C. $108x^5$
• D. $x^2$

Answer 1

The correct option is A $4x^3$

Calomel is $H{g}_{2}C{l}_2$.

It dissociates in the following way, $H{g}_{2}C{l}_2\iff H{g}_2^{2+}+2C{l}^{-}$
$x$ $2x$
$K_{sp}=\left[H{g}_2^{+2}\right]\times [C{l}^{-}{]}^2$

$K_{sp}=x\times (2x{)}^2=4x^3$

Option A is correct.