The solubility of different sparingly soluble salts are given as under:
S. No. Formula Type Solubility Product
1.
2.
3. $A B$
$A_{2} B$
$A B_{3}$ $4.0 \times 10^{- 20}$
$3.2 \times 10^{- 11}$
$2.7 \times 10^{- 31}$
The correct increasing order of solubility is:

1, 3, 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2, 1, 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1. 2, 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3, 1, 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1, 3, 2$
Solubility of $A B = \sqrt{K_{s p}} = 2 \times 10^{- 10}$
Solubility of $A_{2} B = (\frac{K_{s p}}{4})^{1 / 3} = 2 \times 10^{- 4}$
Solubility of $A B_{3} = (\frac{K_{s p}}{27})^{1 / 4} = 10^{- 8}$

Suggest Corrections

Similar questions

\begin{matrix} S . N o . & F o r m u l a T y p e & S o l u b i l i t y p r o d u c t 1. & A B & 4.0 \times 10^{- 20} 2. & A_{2} B & 3.2 \times 10^{- 11} 3. & A B_{3} & 2.7 \times 10^{- 31} \end{matrix}

The solubility product of a sparingly soluble salt $A_{2} B$ is $3.2 \times 10^{- 11}$ . Its solubility in $m o l L^{- 1}$ is:

A X_{2}

3.2 \times 10^{- 11}

A X_{2}

3.2 \times 10^{11}

(m o l e s / l i t r e)

Join BYJU'S Learning Program

S. No.	Formula Type	Solubility Product
1. 2. 3.	$A B$ $A_{2} B$ $A B_{3}$	$4.0 \times 10^{- 20}$ $3.2 \times 10^{- 11}$ $2.7 \times 10^{- 31}$