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Standard XII

Chemistry

Gases in Liquids

The solubilit...

Question

The solubility of $N_{2}$ in water at 300 K and 500 torr, partial pressure is 0.01 g $L^{- 1}$ . The solubility (in g $L^{- 1}$ ) at 750 torr partial pressure is:

0.0075

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0.015

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0.02

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0.005

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Solution

The correct option is A 0.015
From Henry's law,
$\frac{P_{1}}{P_{2}} = \frac{S_{1}}{S_{2}}$ where $S_{1}$ and $S_{2}$ are solubilities.

$\frac{500}{750} = \frac{0.01}{S_{2}}$

$S_{1} = 0.015 g L^{- 1}$

Hence, option B is correct.

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The solubility of N2 in water at 300 K and 500 torr, partial pressure is 0.01 g L−1. The solubility (in g L−1) at 750 torr partial pressure is:

The correct option is A 0.015From Henry's law, P1P2=S1S2 where S1 and S2 are solubilities.500750=0.01S2S1=0.015 gL−1Hence, option B is correct.

The solubility of $N_{2}$ in water at 300 K and 500 torr, partial pressure is 0.01 g $L^{- 1}$ . The solubility (in g $L^{- 1}$ ) at 750 torr partial pressure is:

The correct option is A 0.015
From Henry's law,
$\frac{P_{1}}{P_{2}} = \frac{S_{1}}{S_{2}}$ where $S_{1}$ and $S_{2}$ are solubilities.

$\frac{500}{750} = \frac{0.01}{S_{2}}$

$S_{1} = 0.015 g L^{- 1}$

Hence, option B is correct.