The solubility of $N a_{2} S O_{4}, B e S O_{4}, M g S O_{4}$ and $B a S O_{4}$ in water follow the order :

B a S O_{4} > B e S O_{4} > M g S O_{4} > N a_{2} S O_{4}

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N a_{2} S O_{4} > B e S O_{4} > M g S O_{4} > B a S O_{4}

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B e S O_{4} > M g S O_{4} > B a S O_{4} > N a_{2} S O_{4}

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M g S O_{4} > B e S O_{4} > N a_{2} S P_{4} > B a S O_{4}

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Solution

The correct option is C $B e S O_{4} > M g S O_{4} > B a S O_{4} > N a_{2} S O_{4}$
Decreasing order as size increases solubility increases so
$B e S O_{4} > M g S O_{4} > B a S O_{4} > N a_{2} S O_{4}$

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Similar questions

B e S O_{4}, M g S O_{4}, C a S O_{4}, S r S O_{4}, B a S O_{4}

B e S O_{4}, M g S O_{4}, C a S O_{4}

B e S O_{4}

M g S O_{4}

C a S O_{4}

Why are $B e S O_{4} a n d M g S O_{4}$ readily solubel in water whle $C a S O_{4}, S r S O_{4}$ are insoluble?

B e S O_{4}

M g S O_{4}

B e^{2 +}

M g^{2 +}

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