The solubility of PbCl2 at 25-C is 6-3- 10-3 mole- litre- Its solubility product at that temperature is

The correct option is C (6.3× 10^ 3)× (12.6× 10^ 3)^2 PbCl_2 → S Pb^++ + 2S 2Cl^ K_ sp =S× (2S)^2 = [6.3× 10^ 3]× [12.6× 10^ 3]^2 Option C is ...

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Standard XII

Chemistry

Solubility Product

The solubilit...

Question

The solubility of $P b C l_{2}$ at $25^{\circ} C$ is $6.3 \times 10^{- 3} m o l e / l i t r e$ . Its solubility product at that temperature is_______

(6.3 \times 10^{- 3}) \times (6.3 \times 10^{- 3})

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(6.3 \times 10^{- 3}) \times (12.6 \times 10^{- 3})

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(6.3 \times 10^{- 3}) \times (12.6 \times 10^{- 3})^{2}

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(12.6 \times 10^{- 3}) \times (12.6 \times 10^{- 3})

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Solution

The correct option is C $(6.3 \times 10^{- 3}) \times (12.6 \times 10^{- 3})^{2}$
$P b C l_{2} \to P b^{+ +} S + 2 C l^{-} 2 S$

$K_{s p} = S \times (2 S)^{2} = [6.3 \times 10^{- 3}] \times [12.6 \times 10^{- 3}]^{2}$
Option C is correct.

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The solubility of PbCl2 at 25∘C is 6.3×10−3mole/litre. Its solubility product at that temperature is_______

The correct option is C (6.3×10−3)×(12.6×10−3)2PbCl2→Pb++S+2Cl−2SKsp=S×(2S)2=[6.3×10−3]×[12.6×10−3]2Option C is correct.

The solubility of $P b C l_{2}$ at $25^{\circ} C$ is $6.3 \times 10^{- 3} m o l e / l i t r e$ . Its solubility product at that temperature is_______

The correct option is C $(6.3 \times 10^{- 3}) \times (12.6 \times 10^{- 3})^{2}$
$P b C l_{2} \to P b^{+ +} S + 2 C l^{-} 2 S$

$K_{s p} = S \times (2 S)^{2} = [6.3 \times 10^{- 3}] \times [12.6 \times 10^{- 3}]^{2}$
Option C is correct.