Question

The solubility of potassium chloride (KCl) and Hydrogen chloride (HCl) at different temperatures is given in the table below:

Temperature (degree celsius)	10	20	30	40	50
Solubility (g per 100 ml), KCl	31.2	34.2	37.2	40.1	42.6
Solubility (g per 100 ml), HCl	75	70	65.5	61	57.5

Rohit added 150 g of HCl to 240 mL of water at ${10}^{\circ }C$. Choose the correct outcome.

• A. An unsaturated solution will be formed
• B. A saturated solution will be formed
• C. A suspension will be formed
• D. A supersaturated solution will be formed

Answer 1

The correct option is A An unsaturated solution will be formed

From the table, at ${10}^{\circ }C$, the solubility of HCl = 75 g per 100 ml
Given, amount of solvent = 240 ml
Amount of solute(HCl) = 200 g
Amount of solute that will dissolve in water = Solubility $\times$ Given amount of solvent
= $\frac{75}{100}\times 240$
= 180 g
$\therefore$ 180 g of HCl can be dissolved in water to make a saturated solution.

Here, we have only 150 g, resulting in an unsaturated solution