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Introduction

The solubilit...

Question

The solubility of silver bromide in hypo solution is due to the formation of:

A g_{2} S O_{3}

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A g_{2} S_{2} O_{3}

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[A g (S_{2} O_{3})]^{-}

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[A g (S_{2} O_{3})_{2}]^{3 -}

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Solution

The correct option is D $[A g (S_{2} O_{3})_{2}]^{3 -}$
Unreacted silver bromide $(A g B r)$ can be dissolved from photographic emulsions using 'hypo' solution $(N a_{2} S_{2} O_{3})$ (aq.). The reaction can be represented as:
$A g B r (s) + 3 N a_{2} S_{2} O_{3} (a q) \to N a_{5} A g (S_{2} O_{3})_{3} (a q) + N a B r (a q)$
Hence, option $D$ is correct.

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