The solubility of silver chloride AgCl in water at 25-C is 1-06- 10-5mol L-1- Calculate the solubility product of AgCl at this temperature-

Let AgCl solubility be S Then Ksp=S^2 Given, S=1.06×10^ 5 Ksp=1.1236×10^ 10 ...

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Solubility Product

The solubilit...

Question

The solubility of silver chloride $(A g C l)$ in water at $25^{\circ} C$ is $1.06 \times 10^{- 5} m o l L^{- 1}$ . Calculate the solubility product of $A g C l$ at this temperature.

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A g C l

298 K

1.06 \times 10^{- 5}

25^{o} C

2.28 \times 10^{- 4} S m^{- 1}

d m^{3}

$Λ_{m}^{0} (A g C l) = 138.3 \times 10^{- 4} S m^{2} m o l^{- 1}$
$M (A g C l) = 143.5 g m o l^{- 1}$

A g C l

0.1 M N a C l

25^{o} C

2.0 \times 10^{- 10} m o l^{2} L^{- 2}

A g C l

298 K

1.06 \times 10^{- 5}

5.0 \times 10^{- 13}

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