Question

The solubility product expression for silver (I) sulfide, using x to represent the molar concentration of silver (I) and y to represent the molar concentration of sulfide, is formulated as

• A. $xy$
• B. $x^{2}y$
• C. $x{y}^2$
• D. $x^2{y}^2$
• E. $x{y}^3$

Answer 1

The correct option is B $x^{2}y$

The ionization equilibrium of silver (I) sulfide is $A{g}_{2}S\rightleftharpoons 2A{g}^{+}+S^{2-}$
The solubility product expression for silver (I) sulfide is $K_{SP}\left[A{g}^{+}{]}^2\right[S^{2-}]$.
But $[A{g}^{+}{]}^2=x$ and $\left[S^{2-}\right]=y$.
Hence the expression for the solubility product becomes $K_{SP}\left[A{g}^{+}{]}^2\right[S^{2-}]=x^{2}y$.