You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nersnt Equation

The solubilit...

Question

The solubility product $(K_{s p} i n m o l^{3} d m^{- 9})$ of $M X_{2}$ at $298 K$ based on the information available for the given concentration cell is: (take $2.303 \times R \times 298 / F = 0.059 V)$ .

1 \times 10^{- 15}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 \times 10^{- 15}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 \times 10^{- 12}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 \times 10^{- 12}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $4 \times 10^{- 15}$

Suggest Corrections

Similar questions

(K_{s p} m o l^{3} d m^{- 9})

M X_{2}

2.303 \times R \times 298 / F = 0.059 V

M | M^{2 +}

M X_{2}) | | M^{2 +} (0.001 m o l d m^{- 3}) M .

M^{2 +}

(K_{s p} : m o l^{3} d m^{- 9})

M X_{2}

2.303 \times R \times 298 / F = 0.059 V)

M | M^{2 +}

M X_{2}) | | M^{2 +} (0.001 m o l d m^{- 3}) M .

M^{2 +}

(K_{s p} : m o l^{3} d m^{- 9})

M X_{2}

2.303 \times R \times 298 / F = 0.059 V)

The solubility product of a salt having general formula $M X_{2}$ in water is :

$4 \times 10^{- 12}$ . The concentration of $M^{2 +}$ ions in the aqueous solution of the salt

M X_{2},

4 \times 10^{- 12}

(m o l L^{- 1})

M^{2 +}

Join BYJU'S Learning Program