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Solids in Liquids

The solubilit...

Question

The solubility product $(K_{s p})$ of the following compounds are given at $25^{\circ} C$ . The compound most soluble and least soluble coumpounds are:
Compounds $K_{s p}$
$A g C l 1.1 \times 10^{- 10} A g I 1.1 \times 10^{- 16} P b C r O_{4} 4.0 \times 10^{- 14} A g_{2} C O_{3} 8.0 \times 10^{- 12}$

A g C l a n d P b C r O_{4}

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A g_{2} C O_{3} a n d P b C r O_{4}

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A g_{2} C O_{3} a n d A g I

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A g C l a n d A g_{2} C O_{3}

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Solution

The correct option is C $A g_{2} C O_{3} a n d A g I$
The salts $A g C l, A g I, P b C r O_{4}$ are of same type AB.
So,
Solubility= ${\sqrt{K}}_{s p}$
so,
${Solubility}_{A g C l} = 1 \times 10^{- 5} M$

${Solubility}_{A g I} = 1 \times 10^{- 8} M$

${Solubility}_{P b C r O_{4}} = 2 \times 10^{- 7} M$

For $A g_{2} C O_{3}$ ,
${Solubility}_{A g_{2} C O_{3}} = (\frac{K_{s} p}{4})^{\frac{1}{3}} = 10^{- 4}$

Thus, most soluble is $A g_{2} C O_{3} and least soluble is A g I$

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