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Solubility Product

The solubilit...

Question

The solubility product $(K_{s p})$ of the following compounds are given at $25^{\circ} C$ . The compound most soluble and least soluble coumpounds are:
Compounds $K_{s p}$
$A g C l 1.1 \times 10^{- 10} A g I 1.1 \times 10^{- 16} P b C r O_{4} 4.0 \times 10^{- 14} A g_{2} C O_{3} 8.0 \times 10^{- 12}$

A g C l a n d P b C r O_{4}

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A g_{2} C O_{3} a n d P b C r O_{4}

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A g_{2} C O_{3} a n d A g I

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A g C l a n d A g_{2} C O_{3}

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Solution

The correct option is C $A g_{2} C O_{3} a n d A g I$
The salts $A g C l, A g I, P b C r O_{4}$ are of same type AB.
So,
Solubility= ${\sqrt{K}}_{s p}$
so,
${Solubility}_{A g C l} = 1 \times 10^{- 5} M$

${Solubility}_{A g I} = 1 \times 10^{- 8} M$

${Solubility}_{P b C r O_{4}} = 2 \times 10^{- 7} M$

For $A g_{2} C O_{3}$ ,
${Solubility}_{A g_{2} C O_{3}} = (\frac{K_{s} p}{4})^{\frac{1}{3}} = 10^{- 4}$

Thus, most soluble is $A g_{2} C O_{3} and least soluble is A g I$

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Similar questions

Q. The solubility product

(K_{s p})

of the following compounds are given at

25^{\circ} C

. The compound most soluble and least soluble coumpounds are:
Compounds

K_{s p}

A g C l 1.1 \times 10^{- 10} A g I 1.1 \times 10^{- 16} P b C r O_{4} 4.0 \times 10^{- 14} A g_{2} C O_{3} 8.0 \times 10^{- 12}

Q. Solubility product

(K_{s p})

values of the following sparingly soluble salts at

25^{\circ} C

is :

Salts

K_{s p}

A g C l 1.8 \times 10^{- 10} A g I 1.1 \times 10^{- 16} P b C r O_{4} 1.8 \times 10^{- 14} A g B r 3.3 \times 10^{- 13}

The least soluble and the most soluble salts respectively are:

The $K_{s p}$ of $A g_{2} C r O_{4}$ is $1.1 \times 10^{- 12}$ at 298K. The solubility (in mol/L) of $A g_{2} C r O_{4}$ in 0.1M $A g N O_{3}$ solution is:

Q. The

K_{s p}

A g_{2} C r O_{4}

1.1 \times 10^{- 12}

at 298 K. The solubility (in mole / L) of

A g_{2} C r O_{4}

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Q. The

K_{s p} o f A g_{2} C r O_{4} i s 1.1 \times 10^{- 12} a t 298 K .

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The solubility product (Ksp) of the following compounds are given at 25∘C. The compound most soluble and least soluble coumpounds are: Compounds Ksp AgCl 1.1×10−10AgI 1.1×10−16PbCrO4 4.0×10−14Ag2CO3 8.0×10−12

The correct option is C Ag2CO3 and AgIThe salts AgCl,AgI,PbCrO4 are of same type AB. So, Solubility=√Ksp so, SolubilityAgCl=1×10−5 M SolubilityAgI=1×10−8 M SolubilityPbCrO4=2×10−7 M For Ag2CO3, SolubilityAg2CO3=(Ksp4)13=10−4 Thus, most soluble is Ag2CO3 and least soluble is AgI