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Question

The solubility product of a rare earth metal hydroxide M(OH)3 at room temperature is 4.32×1014. Its solubility is:

A
2×103M
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B
2.0×104M
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C
2×105M
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D
2.0×106M
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Solution

The correct option is A 2×103M
M(OH)3M3++3OH
Ksp for AB3 type molecules is Ksp=27s4
4.32×1014=27s4s4=4.32×101427=16×1012s=2×103M

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