The solubility product of a salt having general formula MX2 in water is 4×10−12. The concentration of M2+ ions in the aqueous solution of the salt is:
A
2.0×10−6M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.0×10−4M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.6×10−4M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4.0×10−10M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B1.0×10−4M Solubility product= 4×10−12 MX2⇌M+2+s2X−2s
If s is solubility, the solubility product Ksp=s×(2s)2 ⇒Ksp=4s3 ⇒s=3√Ksp4 ⇒s=3√4×10−124 ⇒s=1×10−4molL−1