Question

The solubility product of a sparingly soluble salt $A{X}_2$ is $3.2\times {10}^{-11}.$ The value $s^3$ $\left(inmol{L}^{-1}\right)$ is:
where s = solubility

• A. $2\times {10}^{-8}$
• B. $4\times {10}^{-8}$
• C. $4\times {10}^{-13}$
• D. $8\times {10}^{-12}$

Answer 1

The correct option is D $8\times {10}^{-12}$

Given $K_{sp}=3.2\times {10}^{-11}$
The dissociation equation is$A{X}_2\left(s\right)\rightleftharpoons A^{2+}\left(aq\right)+2X^{-}\left(aq\right)t=0100ateqb1-ss2s$
The solubility product is given by:
$K_{sp}=\left[A^{2+}\right][X^{-}{]}^2$
$K_{sp}=s\times (2s{)}^2=4s^3$
$K_{sp}=4s^3=3.2\times {10}^{-11}$
$s^3=8\times {10}^{-12}$