The solubility product of a sparingly soluble salt AX2 is 3.2×10−11. The value s3(inmolL−1) is:
where s = solubility
A
2×10−8
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B
4×10−8
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C
4×10−13
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D
8×10−12
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Solution
The correct option is D8×10−12 Given Ksp=3.2×10−11
The dissociation equation isAX2(s)⇌A2+(aq)+2X−(aq)t=0100ateqb1−ss2s
The solubility product is given by: Ksp=[A2+][X−]2 Ksp=s×(2s)2=4s3 Ksp=4s3=3.2×10−11 s3=8×10−12