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Question

The solubility product of a sparingly soluble salt AX2 is 3.2×1011. The value s3 (in molL1) is:
where s = solubility

A
2×108
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B
4×108
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C
4×1013
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D
8×1012
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Solution

The correct option is D 8×1012
Given Ksp=3.2×1011
The dissociation equation is AX2(s)A2+(aq)+2X(aq)t=0 1 0 0at eqb 1s s 2s
The solubility product is given by:
Ksp=[A2+][X]2
Ksp=s×(2s)2=4s3
Ksp=4s3=3.2×1011
s3=8×1012

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