MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Physical Properties (Group 1)

The solubilit...

Question

The solubility product of Ag₂C₂O₄ at 25⁰C is 1.29×10^-11 mol³ L^-3. Solution ofK₂C₂O₄ containing 0.1520 mole in 500 mL of water is shaken with excess of Ag₂CO₃ till the following equilibrium is reached.
Ag₂CO₃+K₂C₂O₄⇌Ag₂CO₄ + K₂CO₃
At equilibrium the solution contains 0.0358 mole of K₂CO_3- Assuming the degree of dissociation of
K₂CO₃to be equal, the solubility product of Ag₂CO₃ will be

A

1.96×10^-12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

8.48×10^-11

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

1.29×10^-11

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

3.97×10^-12

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
3.97×10^-12

Suggest Corrections

thumbs-up

0

Similar questions

Q. The solubility product of Ag₂C₂O₄ at 25⁰C is 1.29×10^-11 mol³ L^-3. Solution ofK₂C₂O₄ containing 0.1520 mole in 500 mL of water is shaken with excess of Ag₂CO₃ till the following equilibrium is reached.
Ag₂CO₃+K₂C₂O₄⇌Ag₂CO₄ + K₂CO₃
At equilibrium the solution contains 0.0358 mole of K₂CO_3- Assuming the degree of dissociation of K₂CO₃to be equal, the solubility product of Ag₂CO₃ will be

Q. The solubility product of

A g_{2} C_{2} O_{4}

25^{\circ} C

1.29 \times 10^{- 11} m o l^{3} . l i t^{- 3}

. A solution of

K_{2} C_{2} O_{4}

containing 0.1520 moles in 500 ml. Water is shaken at

25^{\circ} C

A g_{2} C O_{3}

till the following equilibrium is reached :

A g_{2} C O_{3} + K_{2} C_{2} O_{4} \to A g_{2} C_{2} O_{4} + K_{2} C O_{3}

. At equilibrium, the solution contains 0.0358 moles of

K_{2} C O_{3}

. Assuming the degree of dissociation of

K_{2} C_{2} O_{4}

K_{2} C O_{3}

to be equal,calculate the solubility product of

A g_{2} C O_{3}

.

Q. The solubility product of

{A g}_{2} C_{2} O_{4}

25^{o} C

1.29 \times 10^{- 11} {m o l}^{3} L^{- 3}

. A solution of

K_{2} C_{2} O_{4}

0.1520 m o l

500 m L

of water is shaken with excess of

{A g}_{2} {C O}_{3}

till the following equilibrium is reached.

{A g}_{2} {C O}_{3} + K_{2} C_{2} O_{4} ⇌ {A g}_{2} C_{2} O_{4} + K_{2} {C O}_{3}

At equilibrium, the solution contains

0.0358 m o l e

K_{2} {C O}_{3}

. Assuming the degree of dissociation of

K_{2} C_{2} O_{4}

K_{2} {C O}_{3}

to be equal, calculate the solubility product of

{A g}_{2} {C O}_{3}

A g C l

was treated with

5.00 m L

1.5 M

N a_{2} C O_{3}

solution to give

A g_{2} C O_{3}

. The remaining solution contained

0.0026 g

C l^{-}

ions per litre. Calculate the solubility product AgCl.

K_{s} p

A g_{2} C O_{3}

8.2 * 10^{- 12}

A sample of $A g C l$ was treated with $500 m L$ of $1.5 M$ $N a_{2} C O_{3}$ solution to give $A g_{2} C O_{3}$ . The remaining solution contained $0.0026 g$ of $C l^{-}$ per litre. The solubility product of $A g C l$ is if $K_{s p} (A g_{2} C O_{3}) = 8.2 \times 10^{- 12}$

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Group 1 - Physical Properties

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Physical Properties (Group 1)

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon