The solubility product of AgCl in water is 10-10 mol 2 L -2 - The solubility of AgCl in 10-1 N solution of KCl at 25- C is approximately in mol L -1A- 10-5 mol - LB- 10-9 mol - LC- 10-7 mol - LD- 10-10 mol - L

The correct option is B 10^ 9 mol/L10^ 1MKCl→10^ 1MK^++10^ 1MCl^ AgCl ⇌ Ag^+ + Cl^ S ⇒ [Cl^ ]_total=(10^ 1+s)=10^ 1 K_SP=10^ 1× s 10^ 10/10^ 1=s s=10^ 9 mol/ ...

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Byju's Answer

Standard XII

Chemistry

Solubility Product

The solubilit...

Question

The solubility product of AgCl in water is $10^{- 10} m o l^{2} L^{- 2}$ . The solubility of AgCl in $10^{- 1} N$ solution of KCl at $25^{\circ} C$ is approximately (in mol $L^{- 1}$ )

10^{- 5} m o l / L

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10^{- 9} m o l / L

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10^{- 7} m o l / L

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10^{- 10} m o l / L

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Solution

The correct option is B $10^{- 9} m o l / L$
$K C l 10^{- 1} M \to K^{+} 10^{- 1} M + C l^{-} 10^{- 1} M$
$A g C l ⇌ A g^{+} + C l^{-}$
$S \Rightarrow [C l^{-}]_{t o t a l} = (10^{- 1} + s) = 10^{- 1}$
$K_{S P} = 10^{- 1} \times s$
$\frac{10^{- 10}}{10^{- 1}} = s$
$s = 10^{- 9} m o l / L$

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Similar questions

Q. The solubility of

A g C l

in water at

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1.06 \times 10^{- 5}

mole per litre. Calculate its solubility product at this temperature.

Q. The solubility of

A g C l

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(K_{s p} = 1.2 \times 10^{- 10})

is ___ mol/L.

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1.5 \times 10^{- 10} m o l^{2} L^{- 2}

Q. Calculate solubility of

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0.1 M N a C l

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if its solubility product at same temperature is

2.0 \times 10^{- 10} m o l^{2} L^{- 2}

Q. The solubility (in mol

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(

K_{s p} = 1.0 \times 10^{- 10}

) in a

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solution will be:

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The solubility product of AgCl in water is 10−10 mol2L−2. The solubility of AgCl in 10−1 N solution of KCl at 25∘ C is approximately (in mol L−1)

The correct option is B 10−9 mol/LKCl10−1M→K+10−1M+Cl−10−1M AgCl⇌Ag++Cl− S⇒[Cl−]total=(10−1+s)=10−1 KSP=10−1×s 10−1010−1=s s=10−9 mol/L

The solubility product of AgCl in water is $10^{- 10} m o l^{2} L^{- 2}$ . The solubility of AgCl in $10^{- 1} N$ solution of KCl at $25^{\circ} C$ is approximately (in mol $L^{- 1}$ )

The correct option is B $10^{- 9} m o l / L$
$K C l 10^{- 1} M \to K^{+} 10^{- 1} M + C l^{-} 10^{- 1} M$
$A g C l ⇌ A g^{+} + C l^{-}$
$S \Rightarrow [C l^{-}]_{t o t a l} = (10^{- 1} + s) = 10^{- 1}$
$K_{S P} = 10^{- 1} \times s$
$\frac{10^{- 10}}{10^{- 1}} = s$
$s = 10^{- 9} m o l / L$