Question

The solubility product of $AgCl$ is $1.5\times {10}^{-10}$. Predict whether there will be any precipitation by mixing $50mL$ of $0.01M$ $NaCl$ and $50mL$ of $0.01M$ $Ag{NO}_3$ solution.

Answer 1

[$A{g}^{+}]=0.01=1\times {10}^{-}2$

[$C{l}^{-}]=0.01=1\times {10}^{-}2$

$K_{SP}=1\times {10}^{-2}\times 1\times {10}^{-2}$

$=1\times {10}^{-4}$

Given $K_{sp}=1.5\times {10}^{-}10$

Since $1\times {10}^{-4}>1.5\times {10}^{-10}$ precipitation occurs.