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Question

The solubility product of an electrolyte is 6912×sn? How many ions (n) will be obtained by the ionization of one molecule of electrolyte?

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Solution

Suppose the electrolytes be Ax Buy
AxByxAv++yBv
S xS yS
Ksp=[Av+]x[Bv]y=(xS)x.(yS)y
=Sx+y.xx.yy
x+y=n and xx.yy=6912
If we put x=3 and y=4 or x=4 and y=3
then xx.yy=33.44=6912
n=x+y=3+4=7

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