Question

The solubility product of an electrolyte is $6912\times s^n$? How many ions ($n$) will be obtained by the ionization of one molecule of electrolyte?

Answer 1

Suppose the electrolytes be $A_x$ Buy

$\therefore$ $A_x{B}_y\rightleftharpoons {xA}^{v+}+y{B}^{v-}$

$S$ $xS$ $yS$

$\therefore$ $K_{sp}={\left[A^{v+}\right]}^x{\left[B^{v-}\right]}^y={\left(xS\right)}^x.{\left(yS\right)}^y$

$=S^{x+y}.x^x.y^y$

$x+y=n$ and $x^x.y^y=6912$

If we put $x=3$ and $y=4$ or $x=4$ and $y=3$

then $x^x.y^y=3^3.4^4=6912$

$\therefore$ $n=x+y=3+4=7$