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Question

The solubility product of CuS,Ag2S and HgS are 10^- 37 ,10^- 44 and 10^-54 respectively the solubility of these sulfides will be in order

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Solution

For CuS &HgS Ksp=S²..(where s= solubility) & for Ag2S ; Ksp=4S³(s= solubility) now put the values of Ksp and check in which case the value of S is highest & lowest.
Solubility of CuS :
(10^-31)^1/2 = ( 10^-31/2);

Ag2S :

(10^-44)^1/3 =( 10^-44/3);

HgS ;

(10^-54)^1/2 = (10^ -54/2) =(10^-27);

The order of solubility will be as per above values:
Hence ,the order of solubility is:

Ag2S> CuS > HgS

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