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Types of Solutions Based on the Concentration of the Solution

The solubilit...

Question

The solubility product of silver iodine is $8.3 \times 10^{- 17}$ and the standard reduction potential of $A g, A g^{+}$ electrode is $+ 0.8$ volts at $25^{o} C$ . The standard reduction potential of $A g, A g I / I^{+}$ electrode from these data is:

- 0.30 V

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+ 0.15 V

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+ 10.0 V

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- 0.15 V

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Solution

The correct option is D $- 0.15 V$
We know,
${E^{0}}_{c e l l} = \frac{0.0591}{n} l o g (\frac{1}{K_{s p}})$
$∴ l o g K_{s p} = - 16.91 \times n [{E^{0}}_{{A g}^{+} / A g} - {E^{0}}_{A g I / A g / I^{0}}]$
$l o g (8.3 \times 10^{- 17}) = - 16.91 \times 1 [0.8 - {E^{0}}_{A g I / A g / I^{0}}]$
$0.95 = 0.8 - {E^{0}}_{A g I / A g / I^{0}}$
${E^{0}}_{A g I / A g / I^{0}} = - 0.15 V$

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83 \times 10^{- 17}

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