The solution of 4 sin 2 x-tan 2 x-cosec2 x- 2 x-6-0 is

The correct option is C n π±π4 (2 sin x cosec x)^2+(tan x x)^2=0 ⇒ sin ^2 x=12 and tan ^2 x=1 ⇒ x=n π±π4, n ∈ Z ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

General Solution of Trigonometric Equation

The solution ...

Question

The solution of $4 {sin}^{2} x + {tan}^{2} x + {cosec}^{2} x + {cot}^{2} x - 6 = 0$ is

n π \pm \frac{π}{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 n π \pm \frac{π}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n π + \frac{π}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n π - \frac{π}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $n π \pm \frac{π}{4}$
$(2 sin x - cosec x)^{2} + (tan x - cot x)^{2} = 0$
$\Rightarrow {sin}^{2} x = \frac{1}{2} and {tan}^{2} x = 1$
$\Rightarrow x = n π \pm \frac{π}{4}, n \in Z$

Suggest Corrections

Similar questions

Q. The range of

x

satisfying

tan x - {tan}^{2} x > 0

and

| 2 sin x | < 1

is
(where

n \in Z

)

Solve the equation: $\sqrt{(\frac{1}{16} + c o s^{4} x - \frac{1}{2} c o s^{2} x)} + \sqrt{(\frac{9}{16} + c o s^{4} x - \frac{3}{2} c o s^{2} x)} = \frac{1}{2}$

Q. The general solution of

tan x + tan 2 x + \sqrt{3} tan x \cdot tan 2 x = \sqrt{3}

(where n \in Z)

Q. If

| 2 sin θ - cosec θ | \geq 1

, then complete set of values of

θ

is
(where

n \in Z

)

Q. The complete solution set of

sin x - \sqrt{3} cos x = 0

Join BYJU'S Learning Program

The solution of 4sin2x+tan2x+cosec2x+cot2x−6=0 is

The correct option is C nπ±π4(2sinx−cosecx)2+(tanx−cotx)2=0⇒sin2x=12 and tan2x=1⇒x=nπ±π4,n∈Z

The solution of $4 {sin}^{2} x + {tan}^{2} x + {cosec}^{2} x + {cot}^{2} x - 6 = 0$ is

The correct option is C $n π \pm \frac{π}{4}$
$(2 sin x - cosec x)^{2} + (tan x - cot x)^{2} = 0$
$\Rightarrow {sin}^{2} x = \frac{1}{2} and {tan}^{2} x = 1$
$\Rightarrow x = n π \pm \frac{π}{4}, n \in Z$