The solution of a quadratic equation $x^{2} + 5 x - 6 = 0$

x = - 1, x = 6

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x = 1, x = - 6

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x = 1

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x = 6

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Solution

The correct option is B $x = 1, x = - 6$
$x^{2} + 5 x - 6 = 0$

Using the factors of $6 = 6 \times 1$

$x^{2} + 6 x - x - 6 = 0$
$x (x + 6) - 1 (x + 6) = 0$
$(x - 1) (x + 6) = 0$

$∴ x - 1 = 0$ and $x + 6 = 0$
$x = 1, x = - 6$

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