The solution of alchohol in water has been prepared by mixing $300$ ml of alchohol with $600$ ml of water. Calculate the volume of solution and concentration of solution.

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Solution

Total volume $= 300 + 600$
$= 900 m l$
concentration of alcohol $= \frac{300}{900} \times 100 %$
$= 33.3 % \frac{v}{v}$

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The solution of alchohol in water has been prepared by mixing 300 ml of alchohol with 600 ml of water. Calculate the volume of solution and concentration of solution.

Total volume =300+600 =900mlconcentration of alcohol =300900×100% =33.3%vv

The solution of alchohol in water has been prepared by mixing $300$ ml of alchohol with $600$ ml of water. Calculate the volume of solution and concentration of solution.

Total volume $= 300 + 600$
$= 900 m l$
concentration of alcohol $= \frac{300}{900} \times 100 %$
$= 33.3 % \frac{v}{v}$