Question

The solution of $\frac{5x}{2}+\frac{3x}{4}\ge \frac{39}{4}$ is

• A. $x\ge 4$
• B. $x\ge 2$
• C. $x\ge 3$
• D. $x\ge 0$

Answer 1

Answer: (C)

$x\ge 3$

$\frac{5x}{2}+\frac{3x}{4}\ge \frac{39}{4}$
Multiply by $4$
$\Rightarrow$ $10x+3x\ge 39$
$\Rightarrow$ $13x\ge 39$
$x\ge 3$
$\therefore$ (3) $x\ge 3$ is correct